LatexRender-ng Project at Sourceforge

This is the LatexRender-ng Project Examples Page

	Markup	Result
1.	[tex style="background: #ccc; padding: 6px;"]\displaystyle \Red{\displaystyle e^x=\sum_{n=0}^\infty\frac{x^n}{n!},\ }\Green{\displaystyle e^x=\sum_{n=0}^\infty\frac{x^n}{n!},\ } \Blue{\displaystyle e^x=\sum_{n=0}^\infty\frac{x^n}{n!}} [/tex]	The colordvi package is used by default, so you can use named colors: $\displaystyle\Red{e^x=\sum_{n=0}^\infty\frac{x^n}{n!},\ }\PineGreen{e^x=\sum_{n=0}^\infty\frac{x^n}{n!},\ }\Blue{e^x=\sum_{n=0}^\infty\frac{x^n}{n!}}$
2.	[preamb] \newcommand{\mycolor}[1]{\Color{0.7 0.8 0.3 0}{#1}} [/preamb] [tex]\displaystyle\mycolor{e=\lim_{x\to +\infty}\left(1+\frac{1}{x}\right)^x}[/tex]	Of course, you can define your own colors! $\displaystyle\mycolor{e=\lim_{x\to +\infty}\left(1+\frac{1}{x}\right)^x}$
3.	[preamb]\DeclareMathOperator{\tr}{tr}[/preamb]	This just adds to the $\LaTeX$ preamble of this page. Nothing should show.
4.	The trace of a square matrix [tex]A[/tex], denoted [tex]\tr A[/tex], is the sum of the elements on its main diagonal.	The trace of a square matrix , denoted $\tr A$ , is the sum of the elements on its main diagonal. Note: this uses the macro \tr defined in the preamble.
5.	[tex]\mathbb{R}^n[/tex]	$\mathbb{R}^n$
6.	[tex fontsize="16"]\mathbb{R}^n[/tex]	$\mathbb{R}^n$
7.	[tex fontsize="8"]\mathbb{R}^n[/tex]	$\mathbb{R}^n$
8.	[tex]x_1+x_2+\cdots+x_n[/tex]	$x_1+x_2+\cdots+x_n$
9.	[tex]F_{n+1}=\sum_{k=0}^n{n-k \choose k}[/tex]	$F_{n+1}=\sum_{k=0}^n{n-k \choose k}$
10.	[tex]\displaystyle F_{n+1}=\sum_{k=0}^n{n-k \choose k}[/tex]	$\displaystyle F_{n+1}=\sum_{k=0}^n{n-k \choose k}$
11.	[tex]n!=n(n-1)(n-2)\cdots 1[/tex]	$n!=n(n-1)(n-2)\cdots 1$
12.	[tex]\displaystyle (a+b)^n=\sum_{k=0}^n{n\choose k}a^kb^{n-k}[/tex]	$\displaystyle (a+b)^n=\sum_{k=0}^n{n\choose k}a^kb^{n-k}$
13.	[tex]\begin{array}{rcl} (x+y)(x-y)&=&x^2-xy+yx-y^2\\ &=&x^2-y^2;\\ (x+y)^2&=&x^2+2xy+y^2& \end{array}[/tex]	$\begin{array}{rcl} (x+y)(x-y)&=&x^2-xy+yx-y^2\\ &=&x^2-y^2;\\ (x+y)^2&=&x^2+2xy+y^2& \end{array}$
14.	[tex style="padding: 4px; border-top: 2px solid #3333ff; border-bottom: 2px solid #3333ff; background: #aaaaee;"]\Red{\det(h_{\lambda_i-i+j})=\pm \det(e_{\mu_i-i+j})}[/tex]	$\Red{\det(h_{\lambda_i-i+j})=\pm \det(e_{\mu_i-i+j})}$
15.	[tex]\begin{array}{rcl} \displaystyle\left(\int_{-\infty}^{+\infty}e^{-x^2}dx\right)^2&=&\displaystyle\int_{-\infty}^{+\infty}\!\!\int_{-\infty}^{+\infty}e^{-x^2-y^2}dx\,dy\\ &=& \displaystyle\int_{0}^{2\pi}\!\!\int_{0}^{+\infty}e^{-r^2}r\,dr\,d\theta\\ &=& \displaystyle\int_{0}^{2\pi}\left(\left.-\frac{e^{-r^2}}{2}\right\|_{r=0}^{r=\infty}\right)d\theta \\ &=& \pi \end{array}[/tex]	$\begin{array}{rcl} \displaystyle\left(\int_{-\infty}^{+\infty}e^{-x^2}dx\right)^2&=&\displaystyle\int_{-\infty}^{+\infty}\!\!\int_{-\infty}^{+\infty}e^{-x^2-y^2}dx\,dy\\ &=& \displaystyle\int_{0}^{2\pi}\!\!\int_{0}^{+\infty}e^{-r^2}r\,dr\,d\theta\\ &=& \displaystyle\int_{0}^{2\pi}\left(\left.-\frac{e^{-r^2}}{2}\right\|_{r=0}^{r=\infty}\right)d\theta \\ &=& \pi \end{array}$
16.	[tex]\displaystyle \sum_{n=1}^{+\infty}\frac{1}{n^2}=1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+\frac{1}{5^2}+\cdots=\frac{\pi^2}{6}[/tex]	$\displaystyle \sum_{n=1}^{+\infty}\frac{1}{n^2}=1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+\frac{1}{5^2}+\cdots=\frac{\pi^2}{6}$
17.	Meaningful error messages help out with the authoring.	Unparseable or potentially dangerous latex formula. Error 6: Image was not produced or one of its dimensions is too small. `\begin{align}{cc} (x-y)^2 &=&x^2-2xy-y^2;\\ (x+y)^2 &=& x^2+2xy+y^2 \end{align}`